(10x^2-3)(10x^2+3)=

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Solution for (10x^2-3)(10x^2+3)= equation:


Simplifying
(10x2 + -3)(10x2 + 3) = 0

Reorder the terms:
(-3 + 10x2)(10x2 + 3) = 0

Reorder the terms:
(-3 + 10x2)(3 + 10x2) = 0

Multiply (-3 + 10x2) * (3 + 10x2)
(-3(3 + 10x2) + 10x2 * (3 + 10x2)) = 0
((3 * -3 + 10x2 * -3) + 10x2 * (3 + 10x2)) = 0
((-9 + -30x2) + 10x2 * (3 + 10x2)) = 0
(-9 + -30x2 + (3 * 10x2 + 10x2 * 10x2)) = 0
(-9 + -30x2 + (30x2 + 100x4)) = 0

Combine like terms: -30x2 + 30x2 = 0
(-9 + 0 + 100x4) = 0
(-9 + 100x4) = 0

Solving
-9 + 100x4 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 100x4 = 0 + 9

Combine like terms: -9 + 9 = 0
0 + 100x4 = 0 + 9
100x4 = 0 + 9

Combine like terms: 0 + 9 = 9
100x4 = 9

Divide each side by '100'.
x4 = 0.09

Simplifying
x4 = 0.09

Reorder the terms:
-0.09 + x4 = 0.09 + -0.09

Combine like terms: 0.09 + -0.09 = 0.00
-0.09 + x4 = 0.00

Factor a difference between two squares.
(0.3 + x2)(-0.3 + x2) = 0.00

Subproblem 1

Set the factor '(0.3 + x2)' equal to zero and attempt to solve: Simplifying 0.3 + x2 = 0 Solving 0.3 + x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-0.3' to each side of the equation. 0.3 + -0.3 + x2 = 0 + -0.3 Combine like terms: 0.3 + -0.3 = 0.0 0.0 + x2 = 0 + -0.3 x2 = 0 + -0.3 Combine like terms: 0 + -0.3 = -0.3 x2 = -0.3 Simplifying x2 = -0.3 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(-0.3 + x2)' equal to zero and attempt to solve: Simplifying -0.3 + x2 = 0 Solving -0.3 + x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '0.3' to each side of the equation. -0.3 + 0.3 + x2 = 0 + 0.3 Combine like terms: -0.3 + 0.3 = 0.0 0.0 + x2 = 0 + 0.3 x2 = 0 + 0.3 Combine like terms: 0 + 0.3 = 0.3 x2 = 0.3 Simplifying x2 = 0.3 Take the square root of each side: x = {-0.547722558, 0.547722558}

Solution

x = {-0.547722558, 0.547722558}

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